object_array_remove_duplicates(): rewrite to reduce copying
The old version copied one entry to its destination position, then deleted any matching entries from the tail of the array. This required the tail of the array to be copied multiple times. It didn't affect the complexity of the algorithm because the whole tail has to be searched through anyway. But all the copying was unnecessary. Instead, check for the existence of an entry with the same name in the *head* of the list before copying an entry to its final position. This way each entry has to be copied at most one time. Extract a helper function contains_name() to do a bit of the work. Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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committed by
Junio C Hamano

parent
be6754c67f
commit
1506510c17
32
object.c
32
object.c
@ -294,22 +294,32 @@ void object_array_filter(struct object_array *array,
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array->nr = dst;
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}
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/*
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* Return true iff array already contains an entry with name.
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*/
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static int contains_name(struct object_array *array, const char *name)
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{
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unsigned nr = array->nr, i;
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struct object_array_entry *object = array->objects;
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for (i = 0; i < nr; i++, object++)
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if (!strcmp(object->name, name))
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return 1;
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return 0;
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}
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void object_array_remove_duplicates(struct object_array *array)
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{
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unsigned int ref, src, dst;
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unsigned nr = array->nr, src;
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struct object_array_entry *objects = array->objects;
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for (ref = 0; ref + 1 < array->nr; ref++) {
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for (src = ref + 1, dst = src;
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src < array->nr;
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src++) {
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if (!strcmp(objects[ref].name, objects[src].name))
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continue;
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if (src != dst)
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objects[dst] = objects[src];
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dst++;
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array->nr = 0;
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for (src = 0; src < nr; src++) {
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if (!contains_name(array, objects[src].name)) {
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if (src != array->nr)
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objects[array->nr] = objects[src];
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array->nr++;
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}
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array->nr = dst;
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}
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}
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