pass constants as first argument to st_mult()
The result of st_mult() is the same no matter the order of its arguments. It invokes the macro unsigned_mult_overflows(), which divides the second parameter by the first one. Pass constants first to allow that division to be done already at compile time. Signed-off-by: Rene Scharfe <l.s.r@web.de> Reviewed-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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Junio C Hamano
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@ -541,7 +541,7 @@ void diffcore_rename(struct diff_options *options)
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rename_dst_nr * rename_src_nr, 50, 1);
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}
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mx = xcalloc(st_mult(num_create, NUM_CANDIDATE_PER_DST), sizeof(*mx));
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mx = xcalloc(st_mult(NUM_CANDIDATE_PER_DST, num_create), sizeof(*mx));
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for (dst_cnt = i = 0; i < rename_dst_nr; i++) {
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struct diff_filespec *two = rename_dst[i].two;
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struct diff_score *m;
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