reftable: make reftable_record a tagged union
This reduces the amount of glue code, because we don't need a void pointer or vtable within the structure. The only snag is that reftable_index_record contain a strbuf, so it cannot be zero-initialized. To address this, use reftable_new_record() to return fresh instance, given a record type. Since reftable_new_record() doesn't cause heap allocation anymore, it should be balanced with reftable_record_release() rather than reftable_record_destroy(). Thanks to Peff for the suggestion. Helped-by: Jeff King <peff@peff.net> Signed-off-by: Han-Wen Nienhuys <hanwen@google.com> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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committed by
Junio C Hamano

parent
9391b88dab
commit
66c0dabab5
@ -31,7 +31,7 @@ static void test_pq(void)
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int N = ARRAY_SIZE(names) - 1;
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struct merged_iter_pqueue pq = { NULL };
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const char *last = NULL;
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char *last = NULL;
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int i = 0;
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for (i = 0; i < N; i++) {
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@ -42,12 +42,10 @@ static void test_pq(void)
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i = 1;
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do {
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struct reftable_record rec =
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reftable_new_record(BLOCK_TYPE_REF);
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struct pq_entry e = { 0 };
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reftable_record_as_ref(&rec)->refname = names[i];
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e.rec = rec;
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struct pq_entry e = { .rec = { .type = BLOCK_TYPE_REF,
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.u.ref = {
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.refname = names[i],
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} } };
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merged_iter_pqueue_add(&pq, e);
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merged_iter_pqueue_check(pq);
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i = (i * 7) % N;
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@ -55,19 +53,18 @@ static void test_pq(void)
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while (!merged_iter_pqueue_is_empty(pq)) {
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struct pq_entry e = merged_iter_pqueue_remove(&pq);
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struct reftable_ref_record *ref =
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reftable_record_as_ref(&e.rec);
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struct reftable_record *rec = &e.rec;
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merged_iter_pqueue_check(pq);
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EXPECT(reftable_record_type(rec) == BLOCK_TYPE_REF);
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if (last) {
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EXPECT(strcmp(last, ref->refname) < 0);
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EXPECT(strcmp(last, rec->u.ref.refname) < 0);
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}
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last = ref->refname;
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ref->refname = NULL;
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reftable_free(ref);
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// this is names[i], so don't dealloc.
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last = rec->u.ref.refname;
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rec->u.ref.refname = NULL;
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reftable_record_release(rec);
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}
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for (i = 0; i < N; i++) {
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reftable_free(names[i]);
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}
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