submodule: check for NULL return of get_submodule_ref_store()
If we can't find a ref store for a submodule then assume the latter is not initialized (or was removed). Print a status line accordingly instead of causing a segmentation fault by passing NULL as the first parameter of refs_head_ref(). Reported-by: Jeremy Feusi <jeremy@feusi.co> Reviewed-by: Stefan Beller <sbeller@google.com> Initial-Test-By: Stefan Beller <sbeller@google.com> Helped-by: Eric Sunshine <sunshine@sunshineco.com> Signed-off-by: Rene Scharfe <l.s.r@web.de> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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Junio C Hamano
parent
d32eb83c1d
commit
74b6bda32f
@ -620,9 +620,13 @@ static void status_submodule(const char *path, const struct object_id *ce_oid,
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displaypath);
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} else if (!(flags & OPT_CACHED)) {
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struct object_id oid;
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struct ref_store *refs = get_submodule_ref_store(path);
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if (refs_head_ref(get_submodule_ref_store(path),
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handle_submodule_head_ref, &oid))
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if (!refs) {
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print_status(flags, '-', path, ce_oid, displaypath);
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goto cleanup;
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}
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if (refs_head_ref(refs, handle_submodule_head_ref, &oid))
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die(_("could not resolve HEAD ref inside the "
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"submodule '%s'"), path);
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