submodule: check for NULL return of get_submodule_ref_store()

If we can't find a ref store for a submodule then assume the latter
is not initialized (or was removed).  Print a status line accordingly
instead of causing a segmentation fault by passing NULL as the first
parameter of refs_head_ref().

Reported-by: Jeremy Feusi <jeremy@feusi.co>
Reviewed-by: Stefan Beller <sbeller@google.com>
Initial-Test-By: Stefan Beller <sbeller@google.com>
Helped-by: Eric Sunshine <sunshine@sunshineco.com>
Signed-off-by: Rene Scharfe <l.s.r@web.de>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
René Scharfe
2018-03-28 23:14:08 +02:00
committed by Junio C Hamano
parent d32eb83c1d
commit 74b6bda32f
2 changed files with 21 additions and 2 deletions

View File

@ -620,9 +620,13 @@ static void status_submodule(const char *path, const struct object_id *ce_oid,
displaypath);
} else if (!(flags & OPT_CACHED)) {
struct object_id oid;
struct ref_store *refs = get_submodule_ref_store(path);
if (refs_head_ref(get_submodule_ref_store(path),
handle_submodule_head_ref, &oid))
if (!refs) {
print_status(flags, '-', path, ce_oid, displaypath);
goto cleanup;
}
if (refs_head_ref(refs, handle_submodule_head_ref, &oid))
die(_("could not resolve HEAD ref inside the "
"submodule '%s'"), path);