commit: push commit_index update into alloc_commit_node
Whenever we create a commit object via lookup_commit, we give it a unique index to be used with the commit-slab API. The theory is that any "struct commit" we create would follow this code path, so any such struct would get an index. However, callers could use alloc_commit_node() directly (and get multiple commits with index 0). Let's push the indexing into alloc_commit_node so that it's hard for callers to get it wrong. Signed-off-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:

committed by
Junio C Hamano

parent
c335d74d34
commit
969eba6341
12
alloc.c
12
alloc.c
@ -47,10 +47,18 @@ union any_object {
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DEFINE_ALLOCATOR(blob, struct blob)
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DEFINE_ALLOCATOR(tree, struct tree)
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DEFINE_ALLOCATOR(commit, struct commit)
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DEFINE_ALLOCATOR(raw_commit, struct commit)
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DEFINE_ALLOCATOR(tag, struct tag)
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DEFINE_ALLOCATOR(object, union any_object)
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void *alloc_commit_node(void)
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{
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static int commit_count;
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struct commit *c = alloc_raw_commit_node();
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c->index = commit_count++;
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return c;
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}
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static void report(const char *name, unsigned int count, size_t size)
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{
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fprintf(stderr, "%10s: %8u (%"PRIuMAX" kB)\n",
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@ -64,7 +72,7 @@ void alloc_report(void)
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{
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REPORT(blob, struct blob);
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REPORT(tree, struct tree);
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REPORT(commit, struct commit);
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REPORT(raw_commit, struct commit);
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REPORT(tag, struct tag);
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REPORT(object, union any_object);
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}
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