oddballs: send usage() help text to standard output

Using the show_usage_if_asked() helper we introduced earlier, fix
callers of usage() that want to show the help text when explicitly
asked by the end-user.  The help text now goes to the standard
output stream for them.

The callers in this step are oddballs in that their invocations of
usage() are *not* guarded by

	if (argc == 2 && !strcmp(argv[1], "-h")
		usage(...);

There are (unnecessarily) being clever ones that do things like

	if (argc != 2 || !strcmp(argv[1], "-h")
		usage(...);

to say "I know I take only one argument, so argc != 2 is always an
error regardless of what is in argv[].  Ah, by the way, even if argc
is 2, "-h" is a request for usage text, so we do the same".

Some like "git var -h" just do not treat "-h" any specially, and let
it take the same error code paths as a parameter error.

Now we cannot do the same, so these callers are rewrittin to do the
show_usage_and_exit_if_asked() first and then handle the usage error
the way they used to.

Acked-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Junio C Hamano
2025-01-16 13:35:52 -08:00
parent b821c999ca
commit a36a822d7d
5 changed files with 13 additions and 4 deletions

View File

@ -27,7 +27,8 @@ int cmd_upload_archive_writer(int argc,
const char *arg_cmd = "argument ";
int ret;
if (argc != 2 || !strcmp(argv[1], "-h"))
show_usage_if_asked(argc, argv, upload_archive_usage);
if (argc != 2)
usage(upload_archive_usage);
if (!enter_repo(argv[1], 0))