oddballs: send usage() help text to standard output
Using the show_usage_if_asked() helper we introduced earlier, fix callers of usage() that want to show the help text when explicitly asked by the end-user. The help text now goes to the standard output stream for them. The callers in this step are oddballs in that their invocations of usage() are *not* guarded by if (argc == 2 && !strcmp(argv[1], "-h") usage(...); There are (unnecessarily) being clever ones that do things like if (argc != 2 || !strcmp(argv[1], "-h") usage(...); to say "I know I take only one argument, so argc != 2 is always an error regardless of what is in argv[]. Ah, by the way, even if argc is 2, "-h" is a request for usage text, so we do the same". Some like "git var -h" just do not treat "-h" any specially, and let it take the same error code paths as a parameter error. Now we cannot do the same, so these callers are rewrittin to do the show_usage_and_exit_if_asked() first and then handle the usage error the way they used to. Acked-by: Jeff King <peff@peff.net> Signed-off-by: Junio C Hamano <gitster@pobox.com>
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@ -27,7 +27,8 @@ int cmd_upload_archive_writer(int argc,
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const char *arg_cmd = "argument ";
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int ret;
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if (argc != 2 || !strcmp(argv[1], "-h"))
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show_usage_if_asked(argc, argv, upload_archive_usage);
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if (argc != 2)
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usage(upload_archive_usage);
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if (!enter_repo(argv[1], 0))
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