repository: repo_submodule_init to take a submodule struct

When constructing a struct repository for a submodule for some revision
of the superproject where the submodule is not contained in the index,
it may not be present in the working tree currently either. In that
situation giving a 'path' argument is not useful. Upgrade the
repo_submodule_init function to take a struct submodule instead.
The submodule struct can be obtained via submodule_from_{path, name} or
an artificial submodule struct can be passed in.

While we are at it, rename the repository struct in the repo_submodule_init
function, which is to be initialized, to a name that is not confused with
the struct submodule as easily. Perform such renames in similar functions
as well.

Also move its documentation into the header file.

Reviewed-by: Jonathan Tan <jonathantanmy@google.com>
Signed-off-by: Stefan Beller <sbeller@google.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Stefan Beller
2018-11-28 16:27:53 -08:00
committed by Junio C Hamano
parent bcd7337243
commit d5498e0871
6 changed files with 43 additions and 35 deletions

View File

@ -206,17 +206,19 @@ static void show_files(struct repository *repo, struct dir_struct *dir);
static void show_submodule(struct repository *superproject,
struct dir_struct *dir, const char *path)
{
struct repository submodule;
struct repository subrepo;
const struct submodule *sub = submodule_from_path(superproject,
&null_oid, path);
if (repo_submodule_init(&submodule, superproject, path))
if (repo_submodule_init(&subrepo, superproject, sub))
return;
if (repo_read_index(&submodule) < 0)
if (repo_read_index(&subrepo) < 0)
die("index file corrupt");
show_files(&submodule, dir);
show_files(&subrepo, dir);
repo_clear(&submodule);
repo_clear(&subrepo);
}
static void show_ce(struct repository *repo, struct dir_struct *dir,