merge-recursive: avoid losing output and leaking memory holding that output

If opt->buffer_output is less than 2, then merge_trees(),
merge_recursive(), and merge_recursive_generic() are all supposed to
flush the opt->obuf output buffer to stdout and release any memory it
holds.  merge_trees() did not do this.  Move the logic that handles this
for merge_recursive_internal() to merge_finalize() so that all three
methods handle this requirement.

Note that this bug didn't cause any problems currently, because there
are only two callers of merge_trees() right now (a git grep for
'merge_trees(' is misleading because builtin/merge-tree.c also defines a
'merge_tree' function that is unrelated), and only one of those is
called with buffer_output less than 2 (builtin/checkout.c), but it set
opt->verbosity to 0, for which there is only currently one non-error
message that would be shown: "Already up to date!".  However, that one
message can only occur when the merge is utterly trivial (the merge base
tree exactly matches the merge tree), and builtin/checkout.c already
attempts a trivial merge via unpack_trees() before falling back to
merge_trees().

Also, if opt->buffer_output is 2, then the caller is responsible to
handle showing any output in opt->obuf and for free'ing it.  This
requirement might be easy to overlook, so add a comment to
merge-recursive.h pointing it out.  (There are currently two callers
that set buffer_output to 2, both in sequencer.c, and both of which
handle this correctly.)

Signed-off-by: Elijah Newren <newren@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

merge-recursive.h

@@ -38,7 +38,8 @@ struct merge_options {
 	/* console output related options */
 	int verbosity;
 	unsigned buffer_output; /* 1: output at end, 2: keep buffered */
-	struct strbuf obuf;     /* output buffer */
+	struct strbuf obuf;     /* output buffer; if buffer_output == 2, caller
+				 * must handle and call strbuf_release */
 
 	/* miscellaneous control options */
 	const char *subtree_shift;